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| author | Jabier Arraiza Cenoz <jabier.arraiza@marker.es> | 2014-11-23 23:36:49 +0000 |
|---|---|---|
| committer | Jabiertxof <jtx@jtx.marker.es> | 2014-11-23 23:36:49 +0000 |
| commit | 0969085ddf607a7a98cf7fd6d9b10da5fbebe62d (patch) | |
| tree | 59b2bc9ed3412ab2de4c703ef30342dfe2401704 /src/2geom/path-intersection.cpp | |
| parent | refactor from lastApplied (diff) | |
| parent | Fixed a bug pointed by suv running from comand line, also removed another des... (diff) | |
| download | inkscape-0969085ddf607a7a98cf7fd6d9b10da5fbebe62d.tar.gz inkscape-0969085ddf607a7a98cf7fd6d9b10da5fbebe62d.zip | |
fixing to trunk
(bzr r12588.1.34)
Diffstat (limited to 'src/2geom/path-intersection.cpp')
| -rw-r--r-- | src/2geom/path-intersection.cpp | 33 |
1 files changed, 24 insertions, 9 deletions
diff --git a/src/2geom/path-intersection.cpp b/src/2geom/path-intersection.cpp index ff24b92eb..63a29423d 100644 --- a/src/2geom/path-intersection.cpp +++ b/src/2geom/path-intersection.cpp @@ -164,20 +164,35 @@ void append(T &a, T const &b) { bool linear_intersect(Point A0, Point A1, Point B0, Point B1, double &tA, double &tB, double &det) { - // kramers rule as cross products + bool both_lines_non_zero = (!are_near(A0, A1)) && (!are_near(B0, B1)); + + // Cramer's rule as cross products Point Ad = A1 - A0, Bd = B1 - B0, d = B0 - A0; det = cross(Ad, Bd); - if( 1.0 + det == 1.0 ) - return false; - else - { - double detinv = 1.0 / det; - tA = cross(d, Bd) * detinv; - tB = cross(d, Ad) * detinv; - return tA >= 0. && tA <= 1. && tB >= 0. && tB <= 1.; + + double det_rel = det; // Calculate the determinant of the normalized vectors + if (both_lines_non_zero) { + det_rel /= Ad.length(); + det_rel /= Bd.length(); } + + if( fabs(det_rel) < 1e-12 ) { // If the cross product is NEARLY zero, + // Then one of the linesegments might have length zero + if (both_lines_non_zero) { + // If that's not the case, then we must have either: + // - parallel lines, with no intersections, or + // - coincident lines, with an infinite number of intersections + // Either is quite useless, so we'll just bail out + return false; + } // Else, one of the linesegments is zero, and we might still be able to calculate a single intersection point + } // Else we haven't bailed out, and we'll try to calculate the intersections + + double detinv = 1.0 / det; + tA = cross(d, Bd) * detinv; + tB = cross(d, Ad) * detinv; + return (tA >= 0.) && (tA <= 1.) && (tB >= 0.) && (tB <= 1.); } |
